UMPIRY

Teodor Leahu vs Sergiu Rogoveanu — Romania F4 Qualifying Round of 16

Romania F4Q16QualifyingClayMon 16 JunFinal
Teodor LeahuROU
Sergiu RogoveanuROU
SetsGames2
76
0
51

Teodor Leahu defeated Sergiu Rogoveanu 7-5 6-1 in the Romania F4 qualifying round of 16 on clay.

Key context

  • Match story: Teodor Leahu came through a tight passage before pulling clear — 7–5 6–1.

How the match was decided

Auto-generated

Leahu T. took it in straight sets.

Match statistics

Match statistics are not available for this match. They appear once the official scoring feed publishes them.

Common opponents

0 shared · last 12 months
No common opponents in the last 12 months. Surface form and ELO carry more weight here.

Head-to-head

1 meeting · Leahu T. leads 1–0
10

Draw

Closing odds

Player context

Before the match
Leahu T.Rogoveanu S.1 503ELO1 5131 503Clay ELO1 5183–7Last 105–5

Cite this

Teodor Leahu beat Sergiu Rogoveanu 7-5 6-1. Umpiry, "Teodor Leahu vs Sergiu Rogoveanu — Romania F4 Qualifying Round of 16", https://umpiry.com/match/2014-06-16/leahu-vs-rogoveanu-romania-f4-q16?utm_source=cite (as of 16 June 2014).