Radu Albot vs Petru Alexandru Luncanu — Romania F3 Round of 32
Romania F3 · ITF · Round of 32
2 — 0
Sets
Monday, 26 May 2014 ·
clay
Albot R.7-6 6-3
Alexandru Luncanu P.
Albot R.
7762
Alexandru Luncanu P.
6330
Radu Albot defeated Petru Alexandru Luncanu 7-6 6-3 in the Romania F3 round of 32 on clay. The upset overturned the form book — Petru Alexandru Luncanu came in leading the head-to-head 1–0. Radu Albot claimed a first win over Petru Alexandru Luncanu in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Radu Albot closed it out in two sets, 7–6 6–3.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2008-07-28 | Romania F14 | R16 | clay | Petru Alexandru Luncanu | 6-1 7-5 |
Statistics
This season1st serve in·Slight edge
64%
70%
1st serve points won·Slight edge
66%
60%
2nd serve points won·Even
49%
45%
Service points won·Even
60%
56%
Return points won·Slight edge
40%
45%
Break points saved·Slight edge
60%
51%
Aces / match·Slight edge
2.0
0.8
Double faults / match·Even
2.9
2.6
Averages over each player's completed matches in the selected window (199 vs 105). ATP, WTA & Challenger.
Freshness
Recent loadFreshness·
73
—
Albot R.: 5 days rest · 2 matches, 44 games (7d). Higher means fresher. About