Radu Albot vs Teodor Leahu — Romania F3 Round of 16
Romania F3 · ITF · Round of 16
2 — 0
Sets
Monday, 26 May 2014 ·
clay
ROUTeodor Leahu
Last 10 · pre-match
LLWLLWLLLW
Albot R.6-2 6-3
Leahu T.
Albot R.
662
Leahu T.
230
Radu Albot defeated Teodor Leahu 6-2 6-3 in the Romania F3 round of 16 on clay.
Key context
- Match story: Radu Albot dropped just 5 games past Teodor Leahu.
Head to head
No previous meetings on record.
Statistics
This seasonAlbot R.Leahu T.
1st serve in·
64%
—
1st serve points won·
66%
—
2nd serve points won·
49%
—
Service points won·
60%
—
Return points won·
40%
—
Break points saved·
60%
—
Aces / match·
2.0
—
Double faults / match·
2.9
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.