Andrei Patrui vs Teodor Leahu — Romania F1 Round of 32
Romania F1 · ITF · Round of 32
2 — 1
Sets
Monday, 12 May 2014 ·
clay
ROUTeodor Leahu
Last 10 · pre-match
LLWLLWLLLW
Patrui A.4-6 6-2 6-2
Leahu T.
Patrui A.
4662
Leahu T.
6221
Andrei Patrui defeated Teodor Leahu 4-6 6-2 6-2 in the Romania F1 round of 32 on clay. The upset overturned the form book — Teodor Leahu came in leading the head-to-head 1–0. Andrei Patrui claimed a first win over Teodor Leahu in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Andrei Patrui dropped the opening set before beating Teodor Leahu 4–6 6–2 6–2.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2014-07-21 | Romania F9 | R32 | clay | Teodor Leahu | 7-5 6-4 |