Andre Miele vs Christian Lindell — Brazil F16 Round of 16
Brazil F16 · ITF · Round of 16
2 — 0
Sets
Monday, 4 November 2013 ·
clay
Miele A.7-6 7-6
Lindell C.
Miele A.
77772
Lindell C.
62640
Andre Miele defeated Christian Lindell 7-6 7-6 in the Brazil F16 round of 16 on clay. Andre Miele extended the head-to-head to 4–3.
Key context
- Match story: Andre Miele won all two sets in tiebreaks against Christian Lindell.
Head to head
3–3| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2015-04-13 | Chile F4 | R16 | clay | Christian Lindell | 6-2 6-2 |
| 2013-11-25 | Brazil F18 | R16 | clay | Andre Miele | 6-3 7-6(5) |
| 2013-08-19 | Brazil F6 | R16 | hard | Christian Lindell | 7-6(7) 6-4 |
| 2010-10-11 | Brazil F28 | F | clay | Christian Lindell | 7-6(6) 6-2 |
| 2010-08-16 | Brazil F19 | F | clay | Andre Miele | 6-4 1-6 6-4 |
| 2009-11-23 | Brazil F29 | SF | clay | Andre Miele | 7-6(5) 6-1 |
Statistics
This season1st serve in·Slight edge
64%
58%
1st serve points won·Even
65%
69%
2nd serve points won·Even
49%
46%
Service points won·Even
59%
59%
Return points won·Even
39%
38%
Break points saved·Even
58%
59%
Aces / match·Clear edge
2.2
4.4
Double faults / match·Clear edge
2.7
4.0
Averages over each player's completed matches in the selected window (25 vs 141). ATP, WTA & Challenger.