Joao Pedro Sorgi vs Christian Lindell — Brazil F14 Round of 16
Brazil F14 · ITF · Round of 16
2 — 0
Sets
Monday, 28 October 2013 ·
clay
Sorgi J.6-4 7-6
Lindell C.
Sorgi J.
6772
Lindell C.
4640
Joao Pedro Sorgi defeated Christian Lindell 6-4 7-6 in the Brazil F14 round of 16 on clay. The upset overturned the form book — Christian Lindell came in leading the head-to-head 3–0, but Joao Pedro Sorgi had been the form player, winning 5 of their last 10 on clay. Joao Pedro Sorgi claimed a first win over Christian Lindell in four meetings, narrowing the head-to-head to 3–1.
Key context
- Match story: Joao Pedro Sorgi edged Christian Lindell in two tight sets (6–4 7–6).
Head to head
0–3| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-02-29 | USA F9 | R16 | clay | Christian Lindell | 7-6(4) 6-3 |
| 2015-02-09 | Sao Paulo | Q1 | clay | Christian Lindell | 6-0 6-1 |
| 2013-12-09 | Brazil F20 | R32 | clay | Christian Lindell | 6-3 6-0 |
Statistics
This season1st serve in·Even
61%
58%
1st serve points won·Even
69%
68%
2nd serve points won·Even
50%
46%
Service points won·Even
61%
58%
Return points won·Even
39%
38%
Break points saved·Even
58%
59%
Aces / match·Slight edge
3.6
4.4
Double faults / match·Clear edge
3.0
4.1
Averages over each player's completed matches in the selected window (117 vs 123). ATP, WTA & Challenger.