Yannick Mertens vs Mathieu Rodrigues — France F21 Round of 16
France F21 · ITF · Round of 16
2 — 0
Sets
Monday, 21 October 2013 ·
hard
Mertens Y.6-0 7-6
Rodrigues M.
Mertens Y.
6772
Rodrigues M.
0610
Yannick Mertens defeated Mathieu Rodrigues 6-0 7-6 in the France F21 round of 16 on hard. The result followed the form book — Yannick Mertens came in leading the head-to-head 3–0. Yannick Mertens extended the head-to-head to 4–0.
Key context
- Match story: Yannick Mertens handed Mathieu Rodrigues a first-set bagel in a 6–0 7–6 win.
Head to head
3–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2014-02-24 | France F4 | F | hard | Yannick Mertens | 6-2 6-1 |
| 2009-10-19 | Great Britain F15 | SF | hard | Yannick Mertens | 6-2 7-5 |
| 2008-11-03 | Spain F42 | QF | hard | Yannick Mertens | 7-5 6-3 |
Statistics
This season1st serve in·Slight edge
65%
55%
1st serve points won·Even
68%
72%
2nd serve points won·Even
51%
49%
Service points won·Even
62%
62%
Return points won·Even
39%
36%
Break points saved·Even
59%
55%
Aces / match·Clear edge
2.7
4.5
Double faults / match·Slight edge
2.8
2.2
Averages over each player's completed matches in the selected window (200 vs 10). ATP, WTA & Challenger.