Jose Rubin Statham vs Blake Mott — Australia F10 Round of 16
Australia F10 · ITF · Round of 16
2 — 1
Sets
Monday, 14 October 2013 ·
hard
Rubin Statham J.5-7 6-4 6-1
Mott B.
Rubin Statham J.
5662
Mott B.
7411
Jose Rubin Statham defeated Blake Mott 5-7 6-4 6-1 in the Australia F10 round of 16 on hard. The upset overturned the form book — Blake Mott came in ranked #1602, leading the head-to-head 2–0. Jose Rubin Statham claimed a first win over Blake Mott in three meetings, narrowing the head-to-head to 2–1.
Key context
- Match story: Jose Rubin Statham dropped the opening set before beating Blake Mott 5–7 6–4 6–1.
Head to head
0–2| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2016-02-22 | Australia F1 | SF | hard | Blake Mott | 1-6 6-1 6-4 |
| 2015-05-18 | Korea F1 | QF | hard | Blake Mott | 6-2 7-5 |
Statistics
This season1st serve in·Slight edge
62%
69%
1st serve points won·Even
72%
68%
2nd serve points won·Even
52%
48%
Service points won·Even
65%
62%
Return points won·Slight edge
36%
41%
Break points saved·Even
59%
58%
Aces / match·Dominant
6.2
2.7
Double faults / match·Clear edge
2.8
3.8
Averages over each player's completed matches in the selected window (200 vs 200). ATP, WTA & Challenger.
Clutch
Under pressureClutch Rating·Even
0
1
Break points saved·Clear edge
33
16
Break points won·Clear edge
2
24
Deciding sets·Clear edge
6
26
Tiebreaks·
22
—
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About