Theodoros Angelinos vs Alexandros Jakupovic — Greece F14 Qualifying Round
Greece F14 · ITF · Qualifying Round
2 — 0
Sets
Monday, 7 October 2013 ·
hard
Angelinos T.6-3 6-2
Jakupovic A.
Angelinos T.
662
Jakupovic A.
320
Theodoros Angelinos defeated Alexandros Jakupovic 6-3 6-2 in the Greece F14 qualifying round on hard. The upset overturned the form book — Alexandros Jakupovic came in leading the head-to-head 3–2. Theodoros Angelinos narrowed the head-to-head to 3–3.
Key context
- Match story: Theodoros Angelinos dropped just 5 games past Alexandros Jakupovic.
Head to head
2–3| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-05-06 | Greece F6 | QF | hard | Alexandros Jakupovic | 3-6 6-2 6-1 |
| 2011-03-14 | Portugal F3 | R32 | hard | Alexandros Jakupovic | 6-3 6-3 |
| 2009-09-21 | Greece F1 | SF | hard | Theodoros Angelinos | 6-7(9) 7-6(6) 7-6(5) |
| 2009-05-11 | Romania F2 | R32 | clay | Theodoros Angelinos | 6-3 3-6 6-4 |
| 2003-08-11 | Romania F8 | R32 | clay | Alexandros Jakupovic | 6-2 6-3 |
Statistics
This season1st serve in·
54%
—
1st serve points won·
70%
—
2nd serve points won·
48%
—
Service points won·
60%
—
Return points won·
34%
—
Break points saved·
58%
—
Aces / match·
3.5
—
Double faults / match·
3.2
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.