Yannik Reuter vs Leon Schutt — Germany F8 Round of 16
Germany F8 · ITF · Round of 16
2 — 0
Sets
Monday, 1 July 2013 ·
clay
Reuter Y.6-4 6-2
Schutt L.
Reuter Y.
662
Schutt L.
420
Yannik Reuter defeated Leon Schutt 6-4 6-2 in the Germany F8 round of 16 on clay. The result followed the form book — Yannik Reuter came in leading the head-to-head 1–0. Yannik Reuter extended the head-to-head to 2–0.
Key context
- Match story: Yannik Reuter dropped just 6 games past Leon Schutt.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2014-11-10 | Tunisia F7 | R32 | hard | Yannik Reuter | 6-2 6-0 |
Statistics
This season1st serve in·Even
61%
65%
1st serve points won·Slight edge
66%
71%
2nd serve points won·Even
48%
52%
Service points won·Slight edge
59%
64%
Return points won·Even
39%
39%
Break points saved·Clear edge
53%
71%
Aces / match·Clear edge
2.4
4.0
Double faults / match·Clear edge
2.5
1.3
Averages over each player's completed matches in the selected window (112 vs 3). ATP, WTA & Challenger.