Felipe Mantilla vs Arthur Surreaux — Mexico F3 Qualifying Round of 64
Mexico F3 · ITF · Qualifying Round of 64
2 — 0
Sets
Monday, 4 February 2013 ·
hard
Mantilla F.6-3 6-4
Surreaux A.
Mantilla F.
662
Surreaux A.
340
Felipe Mantilla defeated Arthur Surreaux 6-3 6-4 in the Mexico F3 qualifying round of 64 on hard. The upset overturned the form book — Arthur Surreaux came in leading the head-to-head 1–0, but Felipe Mantilla had been the form player, winning 2 of their last 5 on hard. Felipe Mantilla claimed a first win over Arthur Surreaux in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Felipe Mantilla closed it out in two sets, 6–3 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-01-28 | Mexico F2 | Q32 | hard | Arthur Surreaux | 5-7 6-2 6-1 |
Statistics
This season1st serve in·Even
62%
65%
1st serve points won·Clear edge
65%
53%
2nd serve points won·Clear edge
49%
31%
Service points won·Clear edge
59%
46%
Return points won·Even
39%
39%
Break points saved·Clear edge
55%
43%
Aces / match·Clear edge
3.1
0.8
Double faults / match·Clear edge
2.9
3.8
Averages over each player's completed matches in the selected window (104 vs 4). ATP, WTA & Challenger.