Yannik Reuter vs Alexandre Penaud — France F2 Round of 32
France F2 · ITF · Round of 32
2 — 0
Sets
Monday, 21 January 2013 ·
hard
Reuter Y.6-4 6-0
Penaud A.
Reuter Y.
662
Penaud A.
400
Yannik Reuter defeated Alexandre Penaud 6-4 6-0 in the France F2 round of 32 on hard. The result followed the form book — Yannik Reuter came in leading the head-to-head 1–0. Yannik Reuter extended the head-to-head to 2–0.
Key context
- Match story: Yannik Reuter handed Alexandre Penaud a second-set bagel in a 6–4 6–0 win.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2012-05-28 | Morocco F2 | R16 | clay | Yannik Reuter | 7-5 6-7(5) 6-3 |
Statistics
This season1st serve in·Even
61%
60%
1st serve points won·Even
66%
70%
2nd serve points won·Even
49%
49%
Service points won·Even
59%
61%
Return points won·Even
39%
36%
Break points saved·Even
54%
58%
Aces / match·Clear edge
2.5
4.4
Double faults / match·Clear edge
2.5
1.7
Averages over each player's completed matches in the selected window (114 vs 12). ATP, WTA & Challenger.