Alexandros Jakupovic vs Yannick Jankovits — Greece F6 Qualifying Round
Greece F6 · ITF · Qualifying Round
2 — 1
Sets
Monday, 5 November 2012 ·
carpet
Jakupovic A.6-4 1-6 7-6
Jankovits Y.
Jakupovic A.
61772
Jankovits Y.
46631
Alexandros Jakupovic defeated Yannick Jankovits 6-4 1-6 7-6 in the Greece F6 qualifying round on carpet. The result followed the form book — Alexandros Jakupovic came in leading the head-to-head 2–0. Alexandros Jakupovic extended the head-to-head to 3–0.
Key context
- Match story: Alexandros Jakupovic closed it out in three sets, 6–4 1–6 7–6.
Head to head
2–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-04-08 | Greece F2 | R16 | hard | Alexandros Jakupovic | 6-1 6-2 |
| 2012-04-09 | Greece F2 | SF | carpet | Alexandros Jakupovic | 7-6(3) 7-6(4) |
Statistics
This season1st serve in·
—
56%
1st serve points won·
—
67%
2nd serve points won·
—
47%
Service points won·
—
58%
Return points won·
—
39%
Break points saved·
—
56%
Aces / match·
—
3.0
Double faults / match·
—
3.3
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.