Roberto Ortega Olmedo vs Matthieu Vierin — Algeria F3 Round of 32
Algeria F3 · ITF · Round of 32
2 — 0
Sets
Monday, 22 October 2012 ·
clay
ITAMatthieu Vierin
Last 10 · pre-match
LLLWLLLWLL
Ortega Olmedo R.6-2 6-3
Vierin M.
Ortega Olmedo R.
662
Vierin M.
230
Roberto Ortega Olmedo defeated Matthieu Vierin 6-2 6-3 in the Algeria F3 round of 32 on clay. The result followed the form book — Roberto Ortega Olmedo came in leading the head-to-head 1–0. Roberto Ortega Olmedo extended the head-to-head to 2–0.
Key context
- Match story: Roberto Ortega Olmedo dropped just 5 games past Matthieu Vierin.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2012-10-15 | Algeria F2 | R16 | clay | Roberto Ortega Olmedo | 6-3 6-2 |
Statistics
This seasonOrtega Olmedo R.Vierin M.
1st serve in·
57%
—
1st serve points won·
66%
—
2nd serve points won·
50%
—
Service points won·
59%
—
Return points won·
38%
—
Break points saved·
55%
—
Aces / match·
2.1
—
Double faults / match·
3.2
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.