Tim Puetz vs Antoine Benneteau — France F16 Round of 16
France F16 · ITF · Round of 16
2 — 0
Sets
Monday, 10 September 2012 ·
hard
Puetz T.7-6 7-6
Benneteau A.
Puetz T.
77772
Benneteau A.
65600
Tim Puetz defeated Antoine Benneteau 7-6 7-6 in the France F16 round of 16 on hard. The result followed the form book — Tim Puetz came in leading the head-to-head 1–0. Tim Puetz extended the head-to-head to 2–0.
Key context
- Match story: Tim Puetz won all two sets in tiebreaks against Antoine Benneteau.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2012-09-24 | France F18 | SF | carpet | Tim Puetz | 3-6 7-6(5) 7-6(4) |
Statistics
This season1st serve in·
56%
—
1st serve points won·
75%
—
2nd serve points won·
52%
—
Service points won·
65%
—
Return points won·
37%
—
Break points saved·
64%
—
Aces / match·
7.3
—
Double faults / match·
3.7
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.