Yannik Reuter vs Alexandre PenaudMorocco F2 Round of 16

Morocco F2 · ITF · Round of 16
35 yrs · Right-handed
Last 10 · pre-match
LLWWWLWLLW
2 — 1
Sets
Monday, 28 May 2012 ·
clay
39 yrs
Last 10 · pre-match
LLLWLLWLWL
Reuter Y.
7-5 6-7 6-3
Penaud A.
Reuter Y.
76562
Penaud A.
57731

Yannik Reuter defeated Alexandre Penaud 7-5 6-7 6-3 in the Morocco F2 round of 16 on clay. The result followed the form book — Yannik Reuter came in leading the head-to-head 1–0. Yannik Reuter extended the head-to-head to 2–0.

Key context

  • Match story: Yannik Reuter closed it out in three sets, 7–5 6–7 6–3.

Head to head

10
DateTournamentRoundSurfaceWinnerScore
2013-01-21France F2R32hardYannik Reuter6-4 6-0

Statistics

This season
1st serve in·Even
61%
63%
1st serve points won·Even
66%
68%
2nd serve points won·Even
49%
46%
Service points won·Even
59%
60%
Return points won·Even
40%
39%
Break points saved·Even
54%
57%
Aces / match·Slight edge
2.3
3.5
Double faults / match·Slight edge
2.5
1.9

Averages over each player's completed matches in the selected window (143 vs 22). ATP, WTA & Challenger.

Draw