Yannik Reuter defeated Alexandre Penaud 7-5 6-7 6-3 in the Morocco F2 round of 16 on clay. The result followed the form book — Yannik Reuter came in leading the head-to-head 1–0. Yannik Reuter extended the head-to-head to 2–0.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2013-01-21 | France F2 | R32 | hard | Yannik Reuter | 6-4 6-0 |
Averages over each player's completed matches in the selected window (143 vs 22). ATP, WTA & Challenger.
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About