Jose Rubin Statham vs Jonathon Cooper — Australia F4 Round of 32
Australia F4 · ITF · Round of 32
2 — 0
Sets
Monday, 26 March 2012 ·
clay
AUSJonathon Cooper
Last 10 · pre-match
LWWLLWLLWL
Rubin Statham J.6-2 6-2
Cooper J.
Rubin Statham J.
662
Cooper J.
220
Jose Rubin Statham defeated Jonathon Cooper 6-2 6-2 in the Australia F4 round of 32 on clay. The result followed the form book — Jose Rubin Statham came in leading the head-to-head 1–0. Jose Rubin Statham extended the head-to-head to 2–0.
Key context
- Match story: Jose Rubin Statham dropped just 4 games past Jonathon Cooper.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2011-04-04 | Australia F4 | R16 | clay | Jose Rubin Statham | 6-4 6-7(2) 6-1 |
Statistics
This seasonRubin Statham J.Cooper J.
1st serve in·
62%
—
1st serve points won·
70%
—
2nd serve points won·
51%
—
Service points won·
63%
—
Return points won·
36%
—
Break points saved·
57%
—
Aces / match·
5.2
—
Double faults / match·
2.8
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.