Benjamin Mitchell vs Jose Rubin Statham — Australia F8 Qualifying Round
Australia F8 · ITF · Qualifying Round
2 — 0
Sets
Monday, 3 October 2011 ·
hard
Mitchell B.7-6 7-6
Rubin Statham J.
Mitchell B.
77772
Rubin Statham J.
63650
Benjamin Mitchell defeated Jose Rubin Statham 7-6 7-6 in the Australia F8 qualifying round on hard. The result followed the form book — Benjamin Mitchell came in leading the head-to-head 3–0. Benjamin Mitchell extended the head-to-head to 4–0.
Key context
- Match story: Benjamin Mitchell won all two sets in tiebreaks against Jose Rubin Statham.
Head to head
3–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2015-11-09 | Australia F10 | SF | hard | Benjamin Mitchell | 6-1 7-6(5) |
| 2011-11-21 | Australia F13 | QF | hard | Benjamin Mitchell | 4-6 6-2 7-6(11) |
| 2010-11-29 | Australia F13 | R16 | hard | Benjamin Mitchell | 7-5 6-0 |
Statistics
This season1st serve in·Even
64%
62%
1st serve points won·Even
68%
72%
2nd serve points won·Slight edge
47%
52%
Service points won·Even
61%
65%
Return points won·Even
39%
36%
Break points saved·Even
61%
59%
Aces / match·Slight edge
4.8
6.2
Double faults / match·Dominant
4.3
2.8
Averages over each player's completed matches in the selected window (91 vs 200). ATP, WTA & Challenger.