Pierre Hugues Herbert vs Albano Olivetti — France F14 Semi-final
France F14 · ITF · Semi-final
#287ATP
1607ELO
1577Hard ELO
35 yrs · 188 cm · Right-handed
Last 10 · pre-match
WLLLLLWWLW
2 — 1
Sets
Monday, 12 September 2011 ·
hard
Hugues Herbert P.3-6 7-6 6-3
Olivetti A.
Hugues Herbert P.
37862
Olivetti A.
66631
Pierre Hugues Herbert defeated Albano Olivetti 3-6 7-6 6-3 in the France F14 semi-final on hard. The upset overturned the form book — Albano Olivetti came in leading the head-to-head 1–0. Pierre Hugues Herbert claimed a first win over Albano Olivetti in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Pierre Hugues Herbert dropped the opening set before beating Albano Olivetti 3–6 7–6 6–3.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2011-10-24 | France F20 | R16 | hard | Albano Olivetti | 7-6(11) 2-6 6-3 |
Statistics
This season1st serve in·Slight edge
60%
55%
1st serve points won·Slight edge
75%
83%
2nd serve points won·Even
49%
50%
Service points won·Even
65%
68%
Return points won·Even
35%
31%
Break points saved·Slight edge
63%
68%
Aces / match·Dominant
8.3
15.9
Double faults / match·Clear edge
5.0
5.8
Averages over each player's completed matches in the selected window (200 vs 190). ATP, WTA & Challenger.