Wesley Koolhof vs Yannik Reuter — Belgium F8 Round of 32
Belgium F8 · ITF · Round of 32
2 — 0
Sets
Monday, 15 August 2011 ·
clay
Koolhof W.7-6 7-6
Reuter Y.
Koolhof W.
787102
Reuter Y.
66680
Wesley Koolhof defeated Yannik Reuter 7-6 7-6 in the Belgium F8 round of 32 on clay. The upset overturned the form book — Yannik Reuter came in leading the head-to-head 1–0. Wesley Koolhof claimed a first win over Yannik Reuter in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Wesley Koolhof won all two sets in tiebreaks against Yannik Reuter.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2011-04-04 | Turkey F12 | R16 | hard | Yannik Reuter | 7-6(6) 2-6 6-2 |
Statistics
This season1st serve in·Even
58%
61%
1st serve points won·Even
67%
66%
2nd serve points won·Even
50%
49%
Service points won·Even
60%
59%
Return points won·Even
37%
40%
Break points saved·Even
57%
54%
Aces / match·Even
2.8
2.3
Double faults / match·Slight edge
2.0
2.5
Averages over each player's completed matches in the selected window (11 vs 143). ATP, WTA & Challenger.