Yannik Reuter vs Alexandre Folie — Belgium F7 Final
Belgium F7 · ITF · Final
2 — 1
Sets
Monday, 8 August 2011 ·
clay
Reuter Y.6-4 4-6 6-0
Folie A.
Reuter Y.
6462
Folie A.
4601
Yannik Reuter defeated Alexandre Folie 6-4 4-6 6-0 in the Belgium F7 final on clay. The upset overturned the form book — Alexandre Folie came in leading the head-to-head 1–0, but Yannik Reuter had been the form player, winning 4 of their last 7 on clay. Yannik Reuter claimed a first win over Alexandre Folie in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Yannik Reuter handed Alexandre Folie a third-set bagel in a 6–4 4–6 6–0 win.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2010-10-11 | Turkey F11 | R32 | hard | Alexandre Folie | 6-3 1-6 7-6(4) |
Statistics
This season1st serve in·Even
61%
62%
1st serve points won·Even
66%
62%
2nd serve points won·Even
49%
46%
Service points won·Even
59%
55%
Return points won·Even
40%
38%
Break points saved·Even
54%
50%
Aces / match·Even
2.3
2.7
Double faults / match·Even
2.5
2.3
Averages over each player's completed matches in the selected window (143 vs 29). ATP, WTA & Challenger.