Yannick Mertens vs Pierre Hugues Herbert — Netherlands F1 Round of 16
Yannick Mertens defeated Pierre Hugues Herbert 6-3 5-7 6-3 in the Netherlands F1 round of 16 on clay. The result followed the form book — Yannick Mertens came in leading the head-to-head 2–0. Yannick Mertens extended the head-to-head to 3–0.
Key context
- Match story: Yannick Mertens closed it out in three sets, 6–3 5–7 6–3.
How the match was decided
Auto-generatedMertens Y. came through in three sets.
Common opponents
0 shared · last 12 monthsNo common opponents in the last 12 months. Surface form and ELO carry more weight here.
Head-to-head
3 meetings · Mertens Y. leads 3–030
Clay: Mertens Y. leads 1–0 · Hard: Mertens Y. leads 2–0
- Mertens Y.June 2011Netherlands F1This matchClay6-3 5-7 6-3
- Mertens Y.February 2011MarseilleHard6-4 1-6 7-5
- Mertens Y.March 2010France F4Hard7-5 6-2
Draw
Closing odds
Next up
Player context
Before the matchMertens Y.Herbert P.1 589ELO1 7421 573Clay ELO1 6222–8Last 103–723Age20185 cmHeight188 cmRightPlaysRight
Cite this
Yannick Mertens beat Pierre Hugues Herbert 6-3 5-7 6-3. Umpiry, "Yannick Mertens vs Pierre Hugues Herbert — Netherlands F1 Round of 16", https://umpiry.com/match/2011-06-06/herbert-vs-mertens-netherlands-f1-r16?utm_source=cite (as of 6 June 2011).