Radu Albot vs Filip Horansky — Turkey F12 Semi-final
Turkey F12 · ITF · Semi-final
2 — 1
Sets
Monday, 4 April 2011 ·
hard
Albot R.4-6 6-0 6-1
Horansky F.
Albot R.
4662
Horansky F.
6011
Radu Albot defeated Filip Horansky 4-6 6-0 6-1 in the Turkey F12 semi-final on hard. The result followed the form book — Radu Albot came in leading the head-to-head 1–0. Radu Albot extended the head-to-head to 2–0.
Key context
- Match story: Radu Albot dropped the opening set before beating Filip Horansky 4–6 6–0 6–1.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2012-02-20 | Turkey F7 | SF | hard | Radu Albot | 6-2 4-6 7-5 |
Statistics
This season1st serve in·Even
64%
64%
1st serve points won·Even
66%
65%
2nd serve points won·Even
49%
47%
Service points won·Even
60%
59%
Return points won·Even
40%
40%
Break points saved·Slight edge
60%
55%
Aces / match·Slight edge
2.0
2.9
Double faults / match·Even
2.9
3.1
Averages over each player's completed matches in the selected window (199 vs 200). ATP, WTA & Challenger.
Freshness
Recent loadFreshness·
55
—
Albot R.: 2 days rest · 4 matches, 107 games (7d). Higher means fresher. About