Nadia Petrova defeated Sofia Arvidsson 6-4 7-6 in the Indian Wells round of 64 on hard. The result followed the form book — Nadia Petrova came in leading the head-to-head 1–0, defending last year's round of 16. Nadia Petrova extended the head-to-head to 2–0.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2005-10-24 | Linz | R16 | hard | Nadia Petrova | 6-3 6-3 |
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Averages over each player's completed matches in the selected window (120 vs 117). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About