Benjamin Mitchell vs Jose Rubin Statham — Australia F13 Round of 16
Australia F13 · ITF · Round of 16
2 — 0
Sets
Monday, 29 November 2010 ·
hard
Mitchell B.7-5 6-0
Rubin Statham J.
Mitchell B.
762
Rubin Statham J.
500
Benjamin Mitchell defeated Jose Rubin Statham 7-5 6-0 in the Australia F13 round of 16 on hard. The result followed the form book — Benjamin Mitchell came in leading the head-to-head 3–0. Benjamin Mitchell extended the head-to-head to 4–0.
Key context
- Match story: Benjamin Mitchell handed Jose Rubin Statham a second-set bagel in a 7–5 6–0 win.
Head to head
3–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2015-11-09 | Australia F10 | SF | hard | Benjamin Mitchell | 6-1 7-6(5) |
| 2011-11-21 | Australia F13 | QF | hard | Benjamin Mitchell | 4-6 6-2 7-6(11) |
| 2011-10-03 | Australia F8 | QF | hard | Benjamin Mitchell | 7-6(3) 7-6(5) |
Statistics
This season1st serve in·Even
64%
62%
1st serve points won·Even
68%
70%
2nd serve points won·Even
47%
51%
Service points won·Even
61%
63%
Return points won·Even
39%
37%
Break points saved·Slight edge
61%
56%
Aces / match·Even
4.9
5.1
Double faults / match·Clear edge
4.2
2.9
Averages over each player's completed matches in the selected window (83 vs 200). ATP, WTA & Challenger.