Amir Weintraub vs Jose Rubin Statham — Australia F12 Round of 16
Australia F12 · ITF · Round of 16
2 — 0
Sets
Monday, 22 November 2010 ·
hard
Weintraub A.6-2 6-1
Rubin Statham J.
Weintraub A.
662
Rubin Statham J.
210
Amir Weintraub defeated Jose Rubin Statham 6-2 6-1 in the Australia F12 round of 16 on hard. The result followed the form book — Amir Weintraub came in leading the head-to-head 2–1. Amir Weintraub extended the head-to-head to 3–1.
Key context
- Match story: Amir Weintraub dropped just 3 games past Jose Rubin Statham.
Head to head
2–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2009-10-26 | Vietnam F1 | F | hard | Jose Rubin Statham | 6-7(4) 7-6(4) 6-1 |
| 2009-10-19 | Thailand F6 | QF | hard | Amir Weintraub | 3-6 6-4 6-3 |
| 2009-10-12 | Thailand F5 | R32 | hard | Amir Weintraub | 2-6 6-3 6-4 |
Statistics
This season1st serve in·Even
66%
63%
1st serve points won·Even
68%
70%
2nd serve points won·Even
50%
51%
Service points won·Even
62%
63%
Return points won·Even
39%
37%
Break points saved·Even
58%
57%
Aces / match·Clear edge
3.4
5.1
Double faults / match·Clear edge
1.9
2.7
Averages over each player's completed matches in the selected window (105 vs 200). ATP, WTA & Challenger.