Yannick Mertens vs Yannick Jankovits — France F19 Round of 32
France F19 · ITF · Round of 32
2 — 0
Sets
Monday, 18 October 2010 ·
hard
Mertens Y.6-0 6-4
Jankovits Y.
Mertens Y.
662
Jankovits Y.
040
Yannick Mertens defeated Yannick Jankovits 6-0 6-4 in the France F19 round of 32 on hard. The upset overturned the form book — Yannick Jankovits came in leading the head-to-head 1–0. Yannick Mertens claimed a first win over Yannick Jankovits in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Yannick Mertens handed Yannick Jankovits a first-set bagel in a 6–0 6–4 win.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2017-10-30 | Israel F15 | F | hard | Yannick Jankovits | 7-5 7-6(6) |
Statistics
This season1st serve in·Slight edge
65%
57%
1st serve points won·Even
68%
69%
2nd serve points won·Even
51%
50%
Service points won·Even
62%
61%
Return points won·Even
39%
42%
Break points saved·Even
59%
57%
Aces / match·Even
2.7
2.9
Double faults / match·Even
2.8
2.8
Averages over each player's completed matches in the selected window (200 vs 109). ATP, WTA & Challenger.