Yannik Reuter defeated Yannick Vandenbulcke 4-6 6-3 6-2 in the Belgium F1 round of 32 on clay. Yannik Reuter extended the head-to-head to 3–2.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2011-07-04 | Belgium F2 | QF | clay | Yannik Reuter | 6-3 5-7 6-2 |
| 2011-06-20 | Germany F6 | QF | clay | Yannick Vandenbulcke | 6-1 4-6 6-4 |
| 2010-10-18 | Turkey F12 | R32 | hard | Yannik Reuter | 6-3 5-7 6-3 |
| 2010-08-16 | Belgium F2 | R16 | clay | Yannick Vandenbulcke | 6-4 5-7 6-2 |
Averages over each player's completed matches in the selected window (143 vs 66). ATP, WTA & Challenger.
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About