Artem Smirnov defeated Petru Alexandru Luncanu 6-4 6-4 in the Romania F1 semi-final on clay. The result followed the form book — Artem Smirnov came in leading the head-to-head 1–0. Artem Smirnov extended the head-to-head to 2–0.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2007-07-02 | Romania F10 | R16 | clay | Artem Smirnov | 2-6 6-1 6-2 |
Averages over each player's completed matches in the selected window (136 vs 107). ATP, WTA & Challenger.
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About