Alexandros Jakupovic vs Romain Hardy — Morocco F1 Round of 32
Alexandros Jakupovic defeated Romain Hardy 6-3 6-7 6-2 in the Morocco F1 round of 32 on clay.
Key context
- Match story: Alexandros Jakupovic closed it out in three sets, 6–3 6–7 6–2.
How the match was decided
Auto-generatedJakupovic A. came through in three sets.
Common opponents
0 shared · last 12 monthsNo common opponents in the last 12 months. Surface form and ELO carry more weight here.
Head-to-head
1 meeting · Jakupovic A. leads 1–010
- Jakupovic A.January 2009Morocco F1This matchClay6-3 6-7(5) 6-2
Draw
Closing odds
Next up
Player context
Before the matchJakupovic A.Hardy R.1 600ELO1 4721 555Clay ELO1 4955–5Last 102–8
Cite this
Alexandros Jakupovic beat Romain Hardy 6-3 6-7(5) 6-2. Umpiry, "Alexandros Jakupovic vs Romain Hardy — Morocco F1 Round of 32", https://umpiry.com/match/2009-01-26/hardy-vs-jakupovic-morocco-f1-r32?utm_source=cite (as of 26 January 2009).