Bogdan Leonte vs Gregory Howe — Iran F4 Round of 32
Bogdan Leonte defeated Gregory Howe 6-1 6-1 in the Iran F4 round of 32 on clay. The result followed the form book — Bogdan Leonte came in leading the head-to-head 1–0. Bogdan Leonte extended the head-to-head to 2–0.
Key context
- Match story: Bogdan Leonte dropped just 2 games past Gregory Howe.
How the match was decided
Auto-generatedLeonte B. took it in straight sets.
Common opponents
0 shared · last 12 monthsNo common opponents in the last 12 months. Surface form and ELO carry more weight here.
Head-to-head
2 meetings · Leonte B. leads 2–020
Clay: Leonte B. leads 1–0 · Grass: Leonte B. leads 1–0
- Leonte B.August 2008Iran F4This matchClay6-1 6-1
- Leonte B.November 2007Pakistan F3Grass6-2 7-6(4)
Draw
Closing odds
Player context
Before the matchLeonte B.Howe G.1 503ELO1 4071 511Clay ELO1 4723–7Last 100–10
Cite this
Bogdan Leonte beat Gregory Howe 6-1 6-1. Umpiry, "Bogdan Leonte vs Gregory Howe — Iran F4 Round of 32", https://umpiry.com/match/2008-08-11/howe-vs-leonte-iran-f4-r32?utm_source=cite (as of 11 August 2008).