Tatiana Golovin defeated Nadia Petrova 6-2 6-1 in the Amelia Island final on clay. The result followed the form book — Tatiana Golovin came in leading the head-to-head 4–1. Tatiana Golovin extended the head-to-head to 5–1.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2007-03-05 | Indian Wells | R16 | hard | Tatiana Golovin | 6-2 1-0 RET |
| 2006-10-02 | Stuttgart | F | clay | Nadia Petrova | 6-3 7-6(4) |
| 2006-08-28 | US Open | R32 | hard | Tatiana Golovin | 7-5 6-7(4) 6-3 |
| 2006-02-06 | Paris | QF | carpet | Tatiana Golovin | 3-6 7-6(7) 6-3 |
| 2005-04-11 | Charleston | QF | clay | Tatiana Golovin | 7-5 6-3 |
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Averages over each player's completed matches in the selected window (57 vs 200). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About