Rabie Chaki vs Alexandre Sidorenko — France F2 Round of 16
France F2 · ITF · Round of 16
2 — 1
Sets
Monday, 29 January 2007 ·
hard
Chaki R.6-7 6-4 6-2
Sidorenko A.
Chaki R.
65662
Sidorenko A.
77421
Rabie Chaki defeated Alexandre Sidorenko 6-7 6-4 6-2 in the France F2 round of 16 on hard. The result followed the form book — Rabie Chaki came in leading the head-to-head 1–0. Rabie Chaki extended the head-to-head to 2–0.
Key context
- Match story: Rabie Chaki dropped the opening set before beating Alexandre Sidorenko 6–7 6–4 6–2.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-03-20 | France F5 | QF | hard | Rabie Chaki | 1-6 6-1 6-4 |
Statistics
This season1st serve in·Clear edge
69%
57%
1st serve points won·Clear edge
54%
73%
2nd serve points won·Even
52%
48%
Service points won·Slight edge
53%
62%
Return points won·Slight edge
43%
37%
Break points saved·Slight edge
51%
59%
Aces / match·Dominant
1.5
5.7
Double faults / match·Dominant
2.0
4.2
Averages over each player's completed matches in the selected window (4 vs 70). ATP, WTA & Challenger.