Bogdan Leonte defeated Teodor Bolanu 6-3 5-7 6-2 in the Romania F16 round of 32 on clay. The upset overturned the form book — Teodor Bolanu came in leading the head-to-head 1–0, but Bogdan Leonte had been the form player, winning 3 of their last 9 on clay. Bogdan Leonte claimed a first win over Teodor Bolanu in two meetings, narrowing the head-to-head to 1–1.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-07-17 | Romania F12 | R16 | clay | Teodor Bolanu | 6-3 6-4 |