Teodor Bolanu defeated Ionut Mihai Beleleu 6-3 6-1 in the Romania F14 round of 32 on clay. The upset overturned the form book — Ionut Mihai Beleleu came in leading the head-to-head 1–0. Teodor Bolanu claimed a first win over Ionut Mihai Beleleu in two meetings, narrowing the head-to-head to 1–1.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2007-08-13 | Romania F16 | R32 | clay | Ionut Mihai Beleleu | 6-0 3-0 |