Wayne Arthurs vs John Van Lottum — Roland Garros Q64
Roland Garros · ATP · Q64
2 — 0
Sets
Wednesday, 24 May 2006 ·
clay
Arthurs W.7-6 6-3
Van Lottum J.
Arthurs W.
7762
Van Lottum J.
6230
Wayne Arthurs defeated John Van Lottum 7-6 6-3 in the Roland Garros q64 on clay. The upset overturned the form book — John Van Lottum came in leading the head-to-head 1–0. Wayne Arthurs claimed a first win over John Van Lottum in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Wayne Arthurs closed it out in two sets, 7–6 6–3.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-10-11 | Singapore | R32 | hard | John Van Lottum | 7-6 7-6 |
Statistics
This season1st serve in·Slight edge
58%
51%
1st serve points won·Clear edge
81%
64%
2nd serve points won·Even
53%
54%
Service points won·Slight edge
69%
59%
Return points won·Even
30%
31%
Break points saved·Slight edge
61%
67%
Aces / match·Dominant
19.0
4.0
Double faults / match·Dominant
5.0
2.0
Averages over each player's completed matches in the selected window (22 vs 1). ATP, WTA & Challenger.
Conditions
Court speed
Slowlow bounce, long rallies
SlowFast