Stian Boretti vs Alexandros Jakupovic — Australia F3 Round of 16
Australia F3 · ITF · Round of 16
2 — 0
Sets
Monday, 13 March 2006 ·
clay
Boretti S.6-2 6-0
Jakupovic A.
Boretti S.
662
Jakupovic A.
200
Stian Boretti defeated Alexandros Jakupovic 6-2 6-0 in the Australia F3 round of 16 on clay. The upset overturned the form book — Alexandros Jakupovic came in leading the head-to-head 1–0. Stian Boretti claimed a first win over Alexandros Jakupovic in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Stian Boretti handed Alexandros Jakupovic a second-set bagel in a 6–2 6–0 win.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2006-03-20 | Australia F4 | QF | clay | Alexandros Jakupovic | 6-4 2-6 6-2 |