Nadia Petrova defeated Antonella Serra Zanetti 6-0 6-1 in the Indian Wells round of 64 on hard. The result followed the form book — Nadia Petrova came in leading the head-to-head 1–0, defending last year's round of 32. Nadia Petrova extended the head-to-head to 2–0.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2005-10-10 | Bangkok | SF | hard | Nadia Petrova | 3-6 6-2 6-4 |
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Averages over each player's completed matches in the selected window (200 vs 17). ATP, WTA & Challenger.