Svetlana Kuznetsova defeated Jessica Kirkland 6-1 6-1 in the Australian Open round of 128 on hard. The result followed the form book — Svetlana Kuznetsova came in leading the head-to-head 1–0, defending last year's round of 32. Svetlana Kuznetsova extended the head-to-head to 2–0.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2003-03-05 | Indian Wells | R128 | hard | Svetlana Kuznetsova | 6-3 6-0 |
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Averages over each player's completed matches in the selected window (197 vs 4). ATP, WTA & Challenger.