Nadia Petrova defeated Anna Lena Groenefeld 7-5 6-3 in the Indian Wells round of 64 on hard. The result followed the form book — Nadia Petrova came in leading the head-to-head 6–1. Nadia Petrova extended the head-to-head to 7–1.
| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2009-05-11 | Madrid | R32 | clay | Nadia Petrova | 4-6 7-6(3) 7-6(5) |
| 2006-10-09 | Moscow | R32 | hard | Nadia Petrova | 6-2 6-2 |
| 2006-10-02 | Stuttgart | R16 | clay | Nadia Petrova | 6-3 6-4 |
| 2006-04-10 | Charleston | SF | clay | Nadia Petrova | 6-1 6-3 |
| 2005-10-03 | Filderstadt | R32 | hard | Nadia Petrova | 6-3 6-2 |
| 2005-09-26 | Luxembourg | QF | hard | Anna Lena Groenefeld | 2-6 6-3 6-2 |
| 2003-09-22 | Leipzig | R16 | carpet | Nadia Petrova | 3-6 6-1 6-4 |
Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About
Averages over each player's completed matches in the selected window (200 vs 140). ATP, WTA & Challenger.
Performance in the biggest moments — break points, deciding sets and tiebreaks (0–100, higher is better). About