Andres Pedroso vs Huntley Montgomery — USA F2 Round of 16
USA F2 · ITF · Round of 16
2 — 0
Sets
Monday, 19 January 2004 ·
hard
USAHuntley Montgomery
Last 10 · pre-match
LLWWWWLLLW
Pedroso A.6-3 6-4
Montgomery H.
Pedroso A.
662
Montgomery H.
340
Andres Pedroso defeated Huntley Montgomery 6-3 6-4 in the USA F2 round of 16 on hard. The upset overturned the form book — Huntley Montgomery came in leading the head-to-head 1–0. Andres Pedroso claimed a first win over Huntley Montgomery in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Andres Pedroso closed it out in two sets, 6–3 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2003-10-20 | USA F29 | R16 | hard | Huntley Montgomery | 6-4 1-6 7-6(4) |
Statistics
This seasonPedroso A.Montgomery H.
1st serve in·
63%
—
1st serve points won·
31%
—
2nd serve points won·
53%
—
Service points won·
39%
—
Return points won·
35%
—
Break points saved·
38%
—
Aces / match·
2.0
—
Double faults / match·
0.0
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.