Alexandros Jakupovic vs Gabriel Moraru — Romania F9 Round of 32
Romania F9 · ITF · Round of 32
2 — 0
Sets
Monday, 18 August 2003 ·
clay
Jakupovic A.6-3 6-4
Moraru G.
Jakupovic A.
662
Moraru G.
340
Alexandros Jakupovic defeated Gabriel Moraru 6-3 6-4 in the Romania F9 round of 32 on clay. The upset overturned the form book — Gabriel Moraru came in leading the head-to-head 1–0. Alexandros Jakupovic claimed a first win over Gabriel Moraru in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Alexandros Jakupovic closed it out in two sets, 6–3 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2002-07-01 | Romania F1 | R16 | clay | Gabriel Moraru | 4-6 6-1 6-4 |
Statistics
This season1st serve in·
—
60%
1st serve points won·
—
50%
2nd serve points won·
—
43%
Service points won·
—
47%
Return points won·
—
35%
Break points saved·
—
52%
Aces / match·
—
1.5
Double faults / match·
—
0.5
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.