Jhonnatan Medina Alvarez vs Roger Anderson — Ecuador F2 Round of 16
Ecuador F2 · ITF · Round of 16
2 — 1
Sets
Monday, 14 July 2003 ·
clay
RSARoger Anderson
Last 10 · pre-match
LLWWWLLLLW
Medina Alvarez J.4-6 6-3 7-6
Anderson R.
Medina Alvarez J.
46772
Anderson R.
63621
Jhonnatan Medina Alvarez defeated Roger Anderson 4-6 6-3 7-6 in the Ecuador F2 round of 16 on clay. The upset overturned the form book — Roger Anderson came in leading the head-to-head 1–0. Jhonnatan Medina Alvarez claimed a first win over Roger Anderson in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Jhonnatan Medina Alvarez dropped the opening set before beating Roger Anderson 4–6 6–3 7–6.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2003-06-16 | Mexico F8 | R32 | hard | Roger Anderson | 6-1 6-1 |