Gabriel Moraru vs Alexandros Jakupovic — Romania F1 Round of 16
Romania F1 · ITF · Round of 16
2 — 1
Sets
Monday, 1 July 2002 ·
clay
Moraru G.4-6 6-1 6-4
Jakupovic A.
Moraru G.
4662
Jakupovic A.
6141
Gabriel Moraru defeated Alexandros Jakupovic 4-6 6-1 6-4 in the Romania F1 round of 16 on clay. The upset overturned the form book — Alexandros Jakupovic came in leading the head-to-head 1–0. Gabriel Moraru claimed a first win over Alexandros Jakupovic in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Gabriel Moraru dropped the opening set before beating Alexandros Jakupovic 4–6 6–1 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2003-08-18 | Romania F9 | R32 | clay | Alexandros Jakupovic | 6-3 6-4 |
Statistics
This season1st serve in·
60%
—
1st serve points won·
50%
—
2nd serve points won·
43%
—
Service points won·
47%
—
Return points won·
35%
—
Break points saved·
52%
—
Aces / match·
1.5
—
Double faults / match·
0.5
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.