Michael Chang vs Guillaume RaouxLos Angeles Round of 16

Los Angeles · ATP · Round of 16
54 yrs · 175 cm · Right-handed
Last 10 · pre-match
LLLLWLLLWL
0 — 0
Sets
Monday, 26 July 1999
hard
56 yrs · 180 cm · Right-handed
Last 10 · pre-match
LLLLLLLLWL
Chang M.
6-4 6-2
Raoux G.
Chang M.
662
Raoux G.
42

Michael Chang defeated Guillaume Raoux 6-4 6-2 in the Los Angeles round of 16 on hard. The upset overturned the form book — Guillaume Raoux came in leading the head-to-head 2–0, defending last year's semi-final, but Michael Chang had been the form player, winning 2 of their last 8 on hard. Michael Chang claimed a first win over Guillaume Raoux in three meetings, narrowing the head-to-head to 2–1.

Key context

Head to head

02
DateTournamentRoundSurfaceWinnerScore
1998-10-26Stuttgart MastersR64carpetGuillaume Raoux7-6(5) 6-3
1998-01-19Australian OpenR64hardGuillaume Raoux6-4 7-6(4) 7-6(5)

Serve vs return

This season
Chang M.serving86% hold

wins 67% of points on serve vs Raoux G.

Raoux G.serving78% hold

wins 62% of points on serve vs Chang M.

Serve advantage — Chang M.

Each player's serve crossed against the other's return, converted to expected hold of serve. Recent completed matches, ATP, WTA & Challenger. About

Statistics

This season
1st serve in·Slight edge
56%
51%
1st serve points won·Even
70%
70%
2nd serve points won·Even
50%
54%
Service points won·Even
61%
62%
Return points won·Slight edge
39%
33%
Break points saved·Even
57%
60%
Aces / match·Slight edge
3.9
4.6
Double faults / match·Dominant
1.7
3.6

Averages over each player's completed matches in the selected window (189 vs 31). ATP, WTA & Challenger.