Tatiana Panova vs Olga Barabanschikova — Oklahoma Round of 32
Oklahoma · WTA · Round of 32
2 — 1
Sets
Monday, 22 February 1999
hard
Panova T.3-6 6-1 6-2
Barabanschikova O.
Panova T.
3662
Barabanschikova O.
6121
Tatiana Panova defeated Olga Barabanschikova 3-6 6-1 6-2 in the Oklahoma round of 32 on hard. The upset overturned the form book — Olga Barabanschikova came in defending last year's round of 32. Tatiana Panova extended the head-to-head to 2–1.
Key context
- Match story: Tatiana Panova dropped the opening set before beating Olga Barabanschikova 3–6 6–1 6–2.
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2003-01-06 | Sydney | QF | hard | Tatiana Panova | 6-3 6-2 |
| 1998-11-16 | Pattaya | R32 | hard | Olga Barabanschikova | 6-2 1-6 6-2 |
Statistics
This season1st serve in·
61%
—
1st serve points won·
54%
—
2nd serve points won·
40%
—
Service points won·
49%
—
Return points won·
40%
—
Break points saved·
51%
—
Aces / match·
0.8
—
Double faults / match·
5.9
—
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Draw
Quarter-finals
Kournikova A.
Rubin C.
7-50-66-3
Coetzer A.
Black C.
6-36-76-3
Osterloh L.
Chi J.
3-66-46-4
Williams V.
Stevenson A.
7-56-3
R16
Kournikova A.
Brandi K.
6-36-1
Coetzer A.
Pampoulova E.
6-16-3
Black C.
Dechaume Balleret A.
7-67-6
Stevenson A.
Panova T.
2-67-67-5
Williams V.
Po Messerli K.
6-17-6
Osterloh L.
Saeki M.
6-46-3
Chi J.
Washington M.
7-66-3
Rubin C.
Pratt N.
6-36-2
R32
Brandi K.
Sanchez Lorenzo M.
7-66-2
Chi J.
Frazier A.
3-67-67-5
Black C.
Snyder T.
6-36-2
Po Messerli K.
Boogert K.
6-46-2
Dechaume Balleret A.
Kremer A.
7-56-4
Pampoulova E.
Nejedly J.
6-46-2
Coetzer A.
Smith N.
4-67-66-4
Rubin C.
Smith S.
6-37-6
Saeki M.
Mcneil L.
7-56-4
Osterloh L.
Raymond L.
2-66-26-2
Stevenson A.
De Swardt M.
7-57-6
Washington M.
Cristea C.
7-66-4
Panova T.
Barabanschikova O.
3-66-16-2
Pratt N.
Shaughnessy M.
6-37-6