Andrea Glass vs Tatiana Panova — Australian Open Round of 64
Australian Open · WTA · Round of 64
2 — 1
Sets
Monday, 18 January 1999 ·
hard
Glass A.7-5 6-7 7-5
Panova T.
Glass A.
7672
Panova T.
5751
Andrea Glass defeated Tatiana Panova 7-5 6-7 7-5 in the Australian Open round of 64 on hard. Andrea Glass extended the head-to-head to 2–1.
Key context
- Match story: Andrea Glass edged Tatiana Panova in three tight sets (7–5 6–7 7–5).
Head to head
1–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 2000-04-30 | Hamburg | R16 | clay | Andrea Glass | 7-6 6-3 |
| 1998-07-25 | Fed Cup WG1 PO: RUS vs GER | RR | hard | Tatiana Panova | 6-3 6-1 |
Statistics
This season1st serve in·
—
61%
1st serve points won·
—
54%
2nd serve points won·
—
40%
Service points won·
—
49%
Return points won·
—
40%
Break points saved·
—
51%
Aces / match·
—
0.8
Double faults / match·
—
5.9
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast