Mary Joe Fernandez vs Chanda Rubin — Stanford Round of 32
Stanford · WTA · Round of 32
0 — 0
Sets
Monday, 27 July 1998
hard
Fernandez M.6-4 6-4
Rubin C.
Fernandez M.
662
Rubin C.
44–
Mary Joe Fernandez defeated Chanda Rubin 6-4 6-4 in the Stanford round of 32 on hard. The upset overturned the form book — Chanda Rubin came in leading the head-to-head 1–0, but Mary Joe Fernandez had been the form player, winning 4 of their last 8 on hard. Mary Joe Fernandez claimed a first win over Chanda Rubin in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Mary Joe Fernandez edged a tight contest from start to finish — 6–4 6–4.
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-01-04 | Auckland | R32 | hard | Chanda Rubin | 7-6 3-6 6-2 |
Statistics
This season1st serve in·
—
63%
1st serve points won·
—
59%
2nd serve points won·
—
48%
Service points won·
—
55%
Return points won·
—
45%
Break points saved·
—
50%
Aces / match·
—
1.4
Double faults / match·
—
2.5
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-fastrewards aggression
SlowFast
Draw
Quarter-finals
Seles M.
Sidot A.
6-36-1
Williams V.
Likhovtseva E.
6-26-4
Graf S.
Zvereva N.
6-16-3
Davenport L.
Tanasugarn T.
7-66-1
R16
Graf S.
Fernandez M.
6-46-0
Seles M.
Li F.
2-66-36-1
Sidot A.
Kruger J.
6-37-6
Williams V.
Morariu C.
4-66-16-0
Likhovtseva E.
Frazier A.
6-16-4
Zvereva N.
Tatarkova E.
0-66-46-2
Davenport L.
Po Messerli K.
6-16-3
Tanasugarn T.
Stevenson A.
6-26-0
R32
Kruger J.
Osterloh L.
1-66-26-4
Li F.
Dechy N.
4-66-46-3
Po Messerli K.
Pratt N.
7-56-0
Tanasugarn T.
Yoshida Y.
6-06-3
Stevenson A.
Grande R.
6-17-5
Sidot A.
Saeki M.
7-66-26-3
Fernandez M.
Rubin C.
6-46-4
Tatarkova E.
Cacic S.
7-62-67-5
Zvereva N.
Snyder T.
6-26-4
Likhovtseva E.
Irvin M.
6-14-66-0
Frazier A.
Lee J.
3-66-26-3
Morariu C.
Capriati J.
6-43-66-4