Paul Hanley vs James Sekulov — Australia 3 Masters 3 Round of 16
Australia 3 Masters 3 · ITF · Round of 16
2 — 0
Sets
Sunday, 28 September 1997 ·
hard
Hanley P.7-5 6-3
Sekulov J.
Hanley P.
762
Sekulov J.
530
Paul Hanley defeated James Sekulov 7-5 6-3 in the Australia 3 Masters 3 round of 16 on hard. The result followed the form book — Paul Hanley came in leading the head-to-head 1–0. Paul Hanley extended the head-to-head to 2–0.
Key context
- Match story: Paul Hanley closed it out in two sets, 7–5 6–3.
Head to head
1–0| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1998-03-01 | Australia 1 Masters 1 | R16 | hard | Paul Hanley | 6-4 6-1 |
Statistics
This season1st serve in·Even
59%
57%
1st serve points won·Slight edge
74%
65%
2nd serve points won·Slight edge
54%
45%
Service points won·Slight edge
66%
56%
Return points won·Slight edge
30%
35%
Break points saved·Dominant
0%
55%
Aces / match·Dominant
6.0
2.4
Double faults / match·Dominant
1.0
3.8
Averages over each player's completed matches in the selected window (1 vs 19). ATP, WTA & Challenger.