Olga Barabanschikova vs Alexandra Stevenson — Indian Wells Round of 64
Indian Wells · WTA · Round of 64
2 — 0
Sets
Friday, 7 March 1997 ·
hard
Barabanschikova O.6-4 7-5
Stevenson A.
Barabanschikova O.
672
Stevenson A.
450
Olga Barabanschikova defeated Alexandra Stevenson 6-4 7-5 in the Indian Wells round of 64 on hard. The upset overturned the form book — Alexandra Stevenson came in leading the head-to-head 1–0, but Olga Barabanschikova had been the form player, winning 5 of their last 9 on hard. Olga Barabanschikova claimed a first win over Alexandra Stevenson in two meetings, narrowing the head-to-head to 1–1.
Key context
- Match story: Olga Barabanschikova edged Alexandra Stevenson in two tight sets (6–4 7–5).
Head to head
0–1| Date | Tournament | Round | Surface | Winner | Score |
|---|---|---|---|---|---|
| 1999-06-21 | Wimbledon | R64 | grass | Alexandra Stevenson | 6-2 6-7 6-3 |
Statistics
This season1st serve in·
—
57%
1st serve points won·
—
66%
2nd serve points won·
—
41%
Service points won·
—
55%
Return points won·
—
37%
Break points saved·
—
60%
Aces / match·
—
4.5
Double faults / match·
—
5.5
Averages over each player's completed matches in the selected window. ATP, WTA & Challenger.
Conditions
Court speed
Medium-slowfavours grinders
SlowFast